factorial
For n = 2 n = 2, which happens to be what has been asked, we have: S2 =(1 0)S0 +(1 1)S1 = 2e S 2 = ( 1 0) S 0 + ( 1 1) S 1 = 2 e. And so on. In general, since Sn S n 's have the same linear recursion relations as Bell numbers Bn B n, the solution would be Sn = eBn S n = e B n.
اقرأ المزيد![](/image/whatsappp.png)